Posted March 6, 2014
Enter the SeaWorld 50th Celebration Sweepstakes for a chance to win 1 of 50 3-day/2-night trips for four to a SeaWorld Park of your Choice!
Fifty winners will receive roundtrip airfare for four to a SeaWorld Park of their Choice, for a 3-day/2-night stay, and 2-day admission to the SeaWorld Park!
Sweepstakes Period #1 – #11 Prizes (44 total winners, 4 winners per Sweepstakes Period): Each winner will receive a 3-day/2-night trip for the winner and up to three (3) guests to a SeaWorld park of his/her choosing (i.e., SeaWorld Orlando, SeaWorld San Antonio or SeaWorld San Diego) (“Trip”).
Sweepstakes Period #12 – #13 Prizes (6 total winners, 3 winners per Sweepstakes Period): Each winner will receive a 3-day/2-night trip for the winner and up to three (3) guests to a SeaWorld park of his/her choosing.
Trip consists of round-trip coach class air transportation for winner and up to three (3) guest(s) to city of Sponsor’s choosing closest to SeaWorld park, from a major commercial airport near winner’s residence (as selected by Sponsor in its sole discretion); 2-night hotel accommodations (one standard room, quadruple occupancy) in a hotel of Sponsor’s choice and two days park admission for four (4), to be used on and around date of trip to SeaWorld Park.
Approximate Retail Value of each prize: $3,200.00.
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