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Savage X Fenty Show Sweepstakes

Posted August 29, 2019

Savage X Fenty Show Sweepstakes
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Win a $7,000 trip for 2 to New York City to attend Rihanna’s Savage X Fenty Show during fashion week!

There will be 2 winners!

Void in Florida, New York, Rhode Island, Puerto Rico.

Entry Frequency:
Single Entry
Eligibility:
Only open to legal residents of the fifty (50) U.S. and the District of Columbia or Canada (excluding Quebec) who are at least 18 years of age or older.
Void in Florida, New York, Rhode Island, Puerto Rico
Start Date:
August 26, 2019
End Date:
August 29, 2019
Official Rules:
View Rules
Prizes:

Two winners will each receive two tickets for themselves and a guest to attend the Savage X Fenty Show in New York City.

Trip includes:

  • round trip economy airfare
  • three (3) nights in one (1) standard hotel room
  • daily stipend up to $1,400
  • two (2) tickets to the Savage X Fenty Show during New York Fashion Week 
  • a gift card for hair and makeup services for the show. 

The approximate value of the Prize is up to $7,000.00 USD

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