Posted April 7, 2014
Enter the Busch Gardens Family Getaway Sweepstakes for a chance to win a 2-night trip for four to either Busch Gardens Tampa Bay or Williamsburg!
One Grand Prize winner will receive roundtrip airfare for four to either Tampa Bay, FL, or Williamsburg, VA, for a 2-night stay, tickets to the Busch Gardens, behind-the-scenes tours of the Park, all-day dining certificates, and travel agent services!
In addition, enter for a chance to win 1 of 25 4-pack of tickets to winner’s choice of Park!
1 GRAND PRIZE: A trip package for four (4) to winner’s choice of Busch Gardens Tampa Bay or Busch Gardens Williamsburg (the “Park”). Trip package includes round trip, coach-class air transportation for four (4) from a major airport near winner’s home (determined by Sponsor in its sole discretion); two (2) nights’ accommodations at Sponsor’s choice of hotel (single room, quadruple occupancy); eight (8) single-day tickets to the applicable Park; four (4) special behind-the-scenes tours at the Park (subject to availability); eight (8) all-day dining certificates (one (1) per person per day at the Park); and travel agent services. Approximate Retail Value (“ARV”): $4,000.
25 FIRST PRIZES: A 4-pack of 1-day tickets to winner’s choice of Park. Tickets expire 6/19/15. Failure to use any ticket prior to the expiration date will result in forfeiture of ticket. ARV: $360.